What is the derivative of 27cos(3x) ?

The derivative of 27cos(3x) is -81sin(3x)

What is the first derivative of 27cos(3x) ?

The first derivative of 27cos(3x) is -81sin(3x)

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\frac{d}{d x} (27 cos (3 x))

- 81 sin (3 x)

Solution steps

\frac{d}{d x} (27 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 27 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 27 (- sin (3 x) \cdot 3)

Simplify

= - 81 sin (3 x)

\int_{1}^{6} t^{4} ln (2 t) d t

\frac{d}{d x} (ln (ln (\frac{1}{x})))

y^{^{'}} + y = 2

\int \frac{1}{15 + 4 t - t ^{2}} d t

\frac{1}{1 - x}, 22

What is the derivative of 27cos(3x) ?
The derivative of 27cos(3x) is -81sin(3x)
What is the first derivative of 27cos(3x) ?
The first derivative of 27cos(3x) is -81sin(3x)