What is the derivative of f(x)=(13-x^4)/3 ?

The derivative of f(x)=(13-x^4)/3 is -(4x^3)/3

What is the first derivative of f(x)=(13-x^4)/3 ?

The first derivative of f(x)=(13-x^4)/3 is -(4x^3)/3

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derivative of

f (x) = \frac{13 - x ^{4}}{3}

- \frac{4 x ^{3}}{3}

Solution steps

\frac{d}{d x} (\frac{13 - x ^{4}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (13 - x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d}{d x} (13) - \frac{d}{d x} (x^{4}))

\frac{d}{d x} (13) = 0

\frac{d}{d x} (x^{4}) = 4 x^{3}

= \frac{1}{3} (0 - 4 x^{3})

Simplify

\frac{1}{3} (0 - 4 x^{3}) : - \frac{4 x ^{3}}{3}

= - \frac{4 x ^{3}}{3}

\int sec^{2} (x) + 6 d x

\frac{( e ^{- 4 s} )}{( s + 2 ) ^{3}}

\frac{\partial}{\partial x} ((x - 3)^{2} + (y - 2)^{2})

{\frac{1}{s ^{4} - 9}}

What is the derivative of f(x)=(13-x^4)/3 ?
The derivative of f(x)=(13-x^4)/3 is -(4x^3)/3
What is the first derivative of f(x)=(13-x^4)/3 ?
The first derivative of f(x)=(13-x^4)/3 is -(4x^3)/3