What is the derivative of y=9e^x+4/(\sqrt[3]{x)} ?

The derivative of y=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

What is the first derivative of y=9e^x+4/(\sqrt[3]{x)} ?

The first derivative of y=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

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derivative of

9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

- 5 t + 3 + t^{7}

\int_{- 2}^{2} t^{3} (3 + t^{4})^{3} d t

h \to + 0 lim (\frac{h}{sin ( 3 h )})

\int (0.3 y^{4} - 8 y^{- 3} + 2) d y

x \to - 1 + lim (x)

What is the derivative of y=9e^x+4/(\sqrt[3]{x)} ?
The derivative of y=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}
What is the first derivative of y=9e^x+4/(\sqrt[3]{x)} ?
The first derivative of y=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}