What is the integral of (cos(x))/(1+8sin(x)) ?

The integral of (cos(x))/(1+8sin(x)) is 1/8 ln|1+8sin(x)|+C

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integral of (cos(x))/(1+8sin(x))

\int \frac{cos ( x )}{1 + 8 sin ( x )} d x

\frac{1}{8} ln ∣ 1 + 8 sin (x) ∣ + C

Solution steps

\int \frac{cos ( x )}{1 + 8 sin ( x )} d x

Apply u-substitution

: \int \frac{1}{8 u} d u

= \int \frac{1}{8 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{8} ln ∣ u ∣

Substitute back

u = 1 + 8 sin (x)

= \frac{1}{8} ln ∣ 1 + 8 sin (x) ∣

Add a constant to the solution

= \frac{1}{8} ln ∣ 1 + 8 sin (x) ∣ + C

\frac{d y}{d x} = (\frac{x}{y})

\frac{4}{x}, 1

\frac{d}{d x} ((3 x^{2} + 3) (2 x^{2} + 1))

2 x^{2} - 2 x + 4

y^{^{'''}} - 9 y^{^{''}} + 18 y^{^{'}} = e^{e^{- 3 x}}

What is the integral of (cos(x))/(1+8sin(x)) ?
The integral of (cos(x))/(1+8sin(x)) is 1/8 ln|1+8sin(x)|+C