What is the derivative of 2x^2-2x+4 ?

The derivative of 2x^2-2x+4 is 4x-2

What is the first derivative of 2x^2-2x+4 ?

The first derivative of 2x^2-2x+4 is 4x-2

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derivative of

2 x^{2} - 2 x + 4

4 x - 2

Solution steps

\frac{d}{d x} (2 x^{2} - 2 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 4 x - 2 + 0

Simplify

= 4 x - 2

y^{^{'''}} - 9 y^{^{''}} + 18 y^{^{'}} = e^{e^{- 3 x}}

\frac{\partial}{\partial t} (\frac{r}{t})

\frac{( m v ^{2} )}{r}

\frac{d y}{d x} = x y + 2 x

\int - \frac{20}{x ^{21}} d x

What is the derivative of 2x^2-2x+4 ?
The derivative of 2x^2-2x+4 is 4x-2
What is the first derivative of 2x^2-2x+4 ?
The first derivative of 2x^2-2x+4 is 4x-2