What is (\partial)/(\partial y)(cos(x)-y) ?

The answer to (\partial)/(\partial y)(cos(x)-y) is -1

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(\partial)/(\partial y)(cos(x)-y)

\frac{\partial}{\partial y} (cos (x) - y)

- 1

Solution steps

\frac{\partial}{\partial y} (cos (x) - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (cos (x)) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (cos (x)) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

\int \frac{x ^{4} + 1}{x ^{4} - 1} d x

\int \frac{2 x - 1}{( x - 1 ) ( x - 2 ) ( 2 x - 3 )} d x

\int \frac{1 + x}{x ^{2} + 2 x - 1} d x

\frac{d}{d x} (e^{- x} cos (y))

\frac{d}{d x} ((1 + x^{3})^{5})

What is (\partial)/(\partial y)(cos(x)-y) ?
The answer to (\partial)/(\partial y)(cos(x)-y) is -1