What is the derivative of (1+x^3^5) ?

The derivative of (1+x^3^5) is 15x^2(1+x^3)^4

What is the first derivative of (1+x^3^5) ?

The first derivative of (1+x^3^5) is 15x^2(1+x^3)^4

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\frac{d}{d x} ((1 + x^{3})^{5})

15 x^{2} (1 + x^{3})^{4}

Solution steps

\frac{d}{d x} ((1 + x^{3})^{5})

Apply the chain rule:

5 (1 + x^{3})^{4} \frac{d}{d x} (1 + x^{3})

= 5 (1 + x^{3})^{4} \frac{d}{d x} (1 + x^{3})

\frac{d}{d x} (1 + x^{3}) = 3 x^{2}

= 5 (1 + x^{3})^{4} \cdot 3 x^{2}

Simplify

= 15 x^{2} (1 + x^{3})^{4}

\frac{\partial}{\partial y} (e^{y} sin (x) y)

\int \frac{x ^{2} sin ( x ) - 2 x + 3}{x ^{2}} d x

\frac{d y}{d t} = - \frac{6}{( 2000 + 6 t )}

\int \frac{e ^{x}}{e ^{2 x} - 1} d x

(\frac{1}{2})^{x} - x

What is the derivative of (1+x^3^5) ?
The derivative of (1+x^3^5) is 15x^2(1+x^3)^4
What is the first derivative of (1+x^3^5) ?
The first derivative of (1+x^3^5) is 15x^2(1+x^3)^4