en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-y^'+(3y)/x =x^2y^2

Solution

- y^{^{'}} + \frac{3 y}{x} = x^{2} y^{2}

Solution

y = \frac{6 x ^{3}}{x ^{6} + c _{1}}

Solution steps

- y^{'} (x) + \frac{3 y}{x} = x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{6 x ^{3}}{x ^{6} + c _{1}}

y = \frac{6 x ^{3}}{x ^{6} + c _{1}}

Popular Examples

integral from 1 to 9 of 2/x

\int_{1}^{9} \frac{2}{x} d x

derivative of-3csc(x^{2/3})

\frac{d}{d x} (- 3 csc (x^{\frac{2}{3}}))

integral of x^{-1}+sin(x)+e^x

\int x^{- 1} + sin (x) + e^{x} d x

(dy)/(dx)+2xy=1

\frac{d y}{d x} + 2 x y = 1

limit as h approaches 0-of (-ln(1+6h))/h

h \to 0 - lim (\frac{- ln ( 1 + 6 h )}{h})

Frequently Asked Questions (FAQ)

What is the solution for -y^'+(3y)/x =x^2y^2 ?
The solution for -y^'+(3y)/x =x^2y^2 is y=(6x^3)/(x^6+c_{1)}