What is the derivative of 5-2/t ?

The derivative of 5-2/t is 2/(t^2)

What is the first derivative of 5-2/t ?

The first derivative of 5-2/t is 2/(t^2)

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derivative of

5 - \frac{2}{t}

\frac{2}{t ^{2}}

Solution steps

\frac{d}{d t} (5 - \frac{2}{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5) - \frac{d}{d t} (\frac{2}{t})

\frac{d}{d t} (5) = 0

\frac{d}{d t} (\frac{2}{t}) = - \frac{2}{t ^{2}}

= 0 - (- \frac{2}{t ^{2}})

Simplify

= \frac{2}{t ^{2}}

\int a x sin (x) d x

\int cosh (7 x) d x

5 x, at x = 16

x \to 1 lim (x^{2} + 4 x)

x \to 3 lim ([8 + 4 (- 10)])

What is the derivative of 5-2/t ?
The derivative of 5-2/t is 2/(t^2)
What is the first derivative of 5-2/t ?
The first derivative of 5-2/t is 2/(t^2)