What is the tangent of 5sqrt(x),\at x=16 ?

The tangent of 5sqrt(x),\at x=16 is y= 5/8 x+10

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tangent of 5sqrt(x),\at x=16

tangent of

5 x, at x = 16

y = \frac{5}{8} x + 10

Solution steps

Find the tangent point:

(16, 20)

Find the slope of

y = 5 x : \frac{d y}{d x} = \frac{5}{2 x}

Compute the slope of

y = 5 x

x = 16 : m = \frac{5}{8}

Find the line with slope m=

\frac{5}{8}

and passing through

(16, 20) : y = \frac{5}{8} x + 10

y = \frac{5}{8} x + 10

x \to 1 lim (x^{2} + 4 x)

x \to 3 lim ([8 + 4 (- 10)])

\int_{- 1}^{4} \frac{1}{∣ x ∣} d x

\frac{\partial}{\partial x} (4 x^{2} - 2 x y + y^{2})

x \to 4 lim (x - \frac{4}{x ^{2} - 16})

What is the tangent of 5sqrt(x),\at x=16 ?
The tangent of 5sqrt(x),\at x=16 is y= 5/8 x+10