What is the derivative of y=(e^{2x})^2 ?

The derivative of y=(e^{2x})^2 is e^{4x}*4

What is the first derivative of y=(e^{2x})^2 ?

The first derivative of y=(e^{2x})^2 is e^{4x}*4

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derivative of

y = (e^{2 x})^{2}

e^{4 x} \cdot 4

Solution steps

\frac{d}{d x} ((e^{2 x})^{2})

Simplify

(e^{2 x})^{2} : e^{4 x}

= \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= e^{4 x} \cdot 4

\frac{d}{d x} (x^{2} + 3 y^{2} - 3)

\frac{d y}{d t} + 5 y = 0

f (x) = \frac{x}{x ^{2} + 9}, at x = 4

f (x) = 2 x^{3}, (2, 16)

x \to 3 + lim (\frac{x ^{2} + 1}{x - 3})

What is the derivative of y=(e^{2x})^2 ?
The derivative of y=(e^{2x})^2 is e^{4x}*4
What is the first derivative of y=(e^{2x})^2 ?
The first derivative of y=(e^{2x})^2 is e^{4x}*4