What is the derivative of sqrt(16-4sin^2(7pix)) ?

The derivative of sqrt(16-4sin^2(7pix)) is -(14pisin(7pix)cos(7pix))/(sqrt(4-sin^2(7pix)))

What is the first derivative of sqrt(16-4sin^2(7pix)) ?

The first derivative of sqrt(16-4sin^2(7pix)) is -(14pisin(7pix)cos(7pix))/(sqrt(4-sin^2(7pix)))

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\frac{d}{d x} (16 - 4 sin^{2} (7 π x))

- \frac{14 π sin ( 7 π x ) cos ( 7 π x )}{4 - sin ^{2} ( 7 π x )}

Solution steps

\frac{d}{d x} (16 - 4 sin^{2} (7 π x))

Apply the chain rule:

\frac{1}{2 16 - 4 sin ^{2} ( 7 π x )} \frac{d}{d x} (16 - 4 sin^{2} (7 π x))

= \frac{1}{2 16 - 4 sin ^{2} ( 7 π x )} \frac{d}{d x} (16 - 4 sin^{2} (7 π x))

\frac{d}{d x} (16 - 4 sin^{2} (7 π x)) = - 56 π sin (7 π x) cos (7 π x)

= \frac{1}{2 16 - 4 sin ^{2} ( 7 π x )} (- 56 π sin (7 π x) cos (7 π x))

Simplify

\frac{1}{2 16 - 4 sin ^{2} ( 7 π x )} (- 56 π sin (7 π x) cos (7 π x)) : - \frac{14 π sin ( 7 π x ) cos ( 7 π x )}{4 - sin ^{2} ( 7 π x )}

= - \frac{14 π sin ( 7 π x ) cos ( 7 π x )}{4 - sin ^{2} ( 7 π x )}

\int_{- 1}^{0} \frac{1}{1 - x ^{2}} d x

f (x) = \frac{1}{2 x}, at x = 25

- \frac{6 x}{x ^{2} + 1}

\frac{d}{d x} (ln ((arcsin (x))^{2}))

\frac{140000}{x}

What is the derivative of sqrt(16-4sin^2(7pix)) ?
The derivative of sqrt(16-4sin^2(7pix)) is -(14pisin(7pix)cos(7pix))/(sqrt(4-sin^2(7pix)))
What is the first derivative of sqrt(16-4sin^2(7pix)) ?
The first derivative of sqrt(16-4sin^2(7pix)) is -(14pisin(7pix)cos(7pix))/(sqrt(4-sin^2(7pix)))