What is the slope of y=(36x)/(x^2+36),(-3,-12/5) ?

The slope of y=(36x)/(x^2+36),(-3,-12/5) is 12/25

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slope of y=(36x)/(x^2+36),(-3,-12/5)

slope

y = \frac{36 x}{x ^{2} + 36}, (- 3, - \frac{12}{5})

\frac{12}{25}

Solution steps

y = \frac{36 x}{x ^{2} + 36}

In order to find the slope of the function, take the derivative of

\frac{36 x}{x ^{2} + 36}

\frac{d}{d x} (\frac{36 x}{x ^{2} + 36}) = \frac{36 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

\frac{36 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

Find the value of

\frac{36 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

for

x = - 3 : \frac{12}{25}

\frac{12}{25}

\frac{d}{d x} (lo g_{5} (x e^{x}))

\int \frac{tan ^{2} ( x )}{4} d x

x^{3 x}

\frac{d}{d x} (\frac{8 x}{5 - tan ( x )})

y^{^{'}} - \frac{6}{x} y = x^{- 4} y^{5}, y (1) = 1

What is the slope of y=(36x)/(x^2+36),(-3,-12/5) ?
The slope of y=(36x)/(x^2+36),(-3,-12/5) is 12/25