What is the solution for y^'-6/x y=x^{-4}y^5,y(1)=1 ?

The solution for y^'-6/x y=x^{-4}y^5,y(1)=1 is y=(\sqrt[4]{21}x^6)/(\sqrt[4]{-4x^{21)+25}}

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y^'-6/x y=x^{-4}y^5,y(1)=1

y^{^{'}} - \frac{6}{x} y = x^{- 4} y^{5}, y (1) = 1

Solution steps

y^{'} (x) - \frac{6}{x} y = x^{- 4} y^{5}

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What is the solution for y^'-6/x y=x^{-4}y^5,y(1)=1 ?
The solution for y^'-6/x y=x^{-4}y^5,y(1)=1 is y=(\sqrt[4]{21}x^6)/(\sqrt[4]{-4x^{21)+25}}