What is the derivative of (x^2-9^2) ?

The derivative of (x^2-9^2) is 4x(x^2-9)

What is the first derivative of (x^2-9^2) ?

The first derivative of (x^2-9^2) is 4x(x^2-9)

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\frac{d}{d x} ((x^{2} - 9)^{2})

4 x (x^{2} - 9)

Solution steps

\frac{d}{d x} ((x^{2} - 9)^{2})

Apply the chain rule:

2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

= 2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= 2 (x^{2} - 9) \cdot 2 x

Simplify

= 4 x (x^{2} - 9)

\frac{\partial}{\partial x} (\frac{- 5 x - y}{y ^{2} + x ^{2}})

\frac{8}{s ^{4}}

x y + y^{^{'}} = 2 x

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

(\frac{10}{3}) t^{2}

What is the derivative of (x^2-9^2) ?
The derivative of (x^2-9^2) is 4x(x^2-9)
What is the first derivative of (x^2-9^2) ?
The first derivative of (x^2-9^2) is 4x(x^2-9)