What is the solution for f^'(x)=(x^2+3)/(cos(x)) ?

The solution for f^'(x)=(x^2+3)/(cos(x)) is f(x)=integral of (x^2+3)/(cos(x))

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f^'(x)=(x^2+3)/(cos(x))

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

Solution steps

f^{'} (x) = \frac{x ^{2} + 3}{cos ( x )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

(\frac{10}{3}) t^{2}

\frac{d}{d n} ((1 + i)^{n} ln (1 + i) + (1 - i)^{n} ln (1 - i))

x \to 5 + lim (- \frac{3}{2} x + \frac{7}{2})

f (x) = \frac{1}{6} x^{4} - 6 x^{2} + 1

cos (sin (x^{5}))

What is the solution for f^'(x)=(x^2+3)/(cos(x)) ?
The solution for f^'(x)=(x^2+3)/(cos(x)) is f(x)=integral of (x^2+3)/(cos(x))