What is the integral from-infinity to-3 of 4/(x^5) ?

The integral from-infinity to-3 of 4/(x^5) is -1/81

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integral from-infinity to-3 of 4/(x^5)

\int_{- \infty}^{- 3} \frac{4}{x ^{5}} d x

- \frac{1}{81}

Decimal Notation

- 0.01234 \dots

Solution steps

\int_{- \infty}^{- 3} \frac{4}{x ^{5}} d x

Compute the indefinite integral:

\int \frac{4}{x ^{5}} d x = - \frac{1}{x ^{4}} + C

Compute the boundaries:

\int_{- \infty}^{- 3} \frac{4}{x ^{5}} d x = - \frac{1}{81} - 0

= - \frac{1}{81} - 0

Simplify

= - \frac{1}{81}

\int + x^{9} x^{5} + 7 d x

\frac{2.99 \cdot 1 0 ^{16}}{r ^{2}}

\frac{\partial}{\partial y} (x y^{2} e^{- x z})

\frac{\partial}{\partial y} (x^{6} - 8 x^{5} y)

g (x) = 4 x^{2} + 10 x - 1

What is the integral from-infinity to-3 of 4/(x^5) ?
The integral from-infinity to-3 of 4/(x^5) is -1/81