What is the derivative of (1(e^x-e^{-x})/2) ?

The derivative of (1(e^x-e^{-x})/2) is 1/2 (e^x+e^{-x})

What is the first derivative of (1(e^x-e^{-x})/2) ?

The first derivative of (1(e^x-e^{-x})/2) is 1/2 (e^x+e^{-x})

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Popular >

\frac{d}{d x} (\frac{1 ( e ^{x} - e ^{- x} )}{2})

\frac{1}{2} (e^{x} + e^{- x})

Solution steps

\frac{d}{d x} (\frac{1 \cdot ( e ^{x} - e ^{- x} )}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (e^{x} - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (e^{x}) - \frac{d}{d x} (e^{- x}))

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= \frac{1}{2} (e^{x} - (- e^{- x}))

Simplify

= \frac{1}{2} (e^{x} + e^{- x})

\int \frac{- 2}{5 x ^{2}} d x

\frac{d y}{d x} - x y^{2} = 2 y x

\frac{d}{d x} (ln (\frac{3 - x}{3 + x}))

\frac{d}{d t} (0.5 t^{2} e^{- 0.6 t})

\int_{- 1}^{5} x - 3 x^{2} d x

What is the derivative of (1(e^x-e^{-x})/2) ?
The derivative of (1(e^x-e^{-x})/2) is 1/2 (e^x+e^{-x})
What is the first derivative of (1(e^x-e^{-x})/2) ?
The first derivative of (1(e^x-e^{-x})/2) is 1/2 (e^x+e^{-x})