What is the solution for (dy)/(dx)-xy^2=2yx ?

The solution for (dy)/(dx)-xy^2=2yx is y= 2/(e^{-x^2-c_{1)}-1}

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(dy)/(dx)-xy^2=2yx

\frac{d y}{d x} - x y^{2} = 2 y x

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

\frac{d y}{d x} - x y^{2} = 2 y x

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

\frac{d}{d x} (ln (\frac{3 - x}{3 + x}))

\frac{d}{d t} (0.5 t^{2} e^{- 0.6 t})

\int_{- 1}^{5} x - 3 x^{2} d x

\int \frac{lo g _{2} ( u )}{u} d x

\frac{d}{d x} (\frac{x}{1 - sin ( x )})

What is the solution for (dy)/(dx)-xy^2=2yx ?
The solution for (dy)/(dx)-xy^2=2yx is y= 2/(e^{-x^2-c_{1)}-1}