What is the integral of (log_{2}(u))/u ?

The integral of (log_{2}(u))/u is (log_{2}(u))/u x+C

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integral of (log_{2}(u))/u

\int \frac{lo g _{2} ( u )}{u} d x

\frac{lo g _{2} ( u )}{u} x + C

Solution steps

\int \frac{lo g _{2} ( u )}{u} d x

Integral of a constant:

\int a d x = a x

= \frac{lo g _{2} ( u )}{u} x

Add a constant to the solution

= \frac{lo g _{2} ( u )}{u} x + C

\frac{d}{d x} (\frac{x}{1 - sin ( x )})

\frac{1}{s ( 2 s ^{2} + 2 s + 1 )}

n = 0 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

\frac{( x ^{2} - 4 x )}{x + 1}

\int \frac{1}{x ^{4}} + 4 d x

What is the integral of (log_{2}(u))/u ?
The integral of (log_{2}(u))/u is (log_{2}(u))/u x+C