What is the sum from n=0 to infinity of 3/(n^{5/3)} ?

The sum from n=0 to infinity of 3/(n^{5/3)} is converges

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sum from n=0 to infinity of 3/(n^{5/3)}

n = 0 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

converges

Solution steps

n = 1 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty \frac{1}{n ^{\frac{5}{3}}}

Apply p-Series Test:

converges

= 3 converges

= converges

\frac{( x ^{2} - 4 x )}{x + 1}

\int \frac{1}{x ^{4}} + 4 d x

\frac{d y}{d x}, x^{3} + y^{3} - 9 x y = 0

f (t) = 1 + e^{4 t}

y = 2 x, (18, 6)

What is the sum from n=0 to infinity of 3/(n^{5/3)} ?
The sum from n=0 to infinity of 3/(n^{5/3)} is converges