What is the derivative of e^{x^2+9x} ?

The derivative of e^{x^2+9x} is e^{x^2+9x}(2x+9)

What is the first derivative of e^{x^2+9x} ?

The first derivative of e^{x^2+9x} is e^{x^2+9x}(2x+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{x^{2} + 9 x})

e^{x^{2} + 9 x} (2 x + 9)

Solution steps

\frac{d}{d x} (e^{x^{2} + 9 x})

Apply the chain rule:

e^{x^{2} + 9 x} \frac{d}{d x} (x^{2} + 9 x)

= e^{x^{2} + 9 x} \frac{d}{d x} (x^{2} + 9 x)

\frac{d}{d x} (x^{2} + 9 x) = 2 x + 9

= e^{x^{2} + 9 x} (2 x + 9)

\int sec^{3} (x) tan^{5} (x) d x

\int 2 x^{3} d x

\int - \frac{1}{2} \cdot sin (2 x) + \frac{1}{4} \cdot 2 x d x

\int x^{5} + 1 d x

\int e^{t a n (3 x)} sec^{2} (3 x) d x

What is the derivative of e^{x^2+9x} ?
The derivative of e^{x^2+9x} is e^{x^2+9x}(2x+9)
What is the first derivative of e^{x^2+9x} ?
The first derivative of e^{x^2+9x} is e^{x^2+9x}(2x+9)