What is the integral of e^{tan(3x)}sec^2(3x) ?

The integral of e^{tan(3x)}sec^2(3x) is 1/3 e^{tan(3x)}+C

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integral of e^{tan(3x)}sec^2(3x)

\int e^{t a n (3 x)} sec^{2} (3 x) d x

\frac{1}{3} e^{t a n (3 x)} + C

Solution steps

\int e^{t a n (3 x)} sec^{2} (3 x) d x

Apply u-substitution

: \int e^{t a n (u)} sec^{2} (u) \frac{1}{3} d u

= \int e^{t a n (u)} sec^{2} (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int e^{t a n (u)} sec^{2} (u) d u

Apply u-substitution

: \int e^{v} d v

= \frac{1}{3} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= \frac{1}{3} e^{v}

Substitute back

= \frac{1}{3} e^{t a n (3 x)}

Add a constant to the solution

= \frac{1}{3} e^{t a n (3 x)} + C

\frac{d}{d x} (\frac{f ( x ) g ( x )}{x})

- y^{^{''}} + y = 1

\int_{0}^{l n (8)} x e^{x} d x

f (x) = - x^{2} + 3, g (x) = 2 x + 3

x \to - 7 lim (x)

What is the integral of e^{tan(3x)}sec^2(3x) ?
The integral of e^{tan(3x)}sec^2(3x) is 1/3 e^{tan(3x)}+C