What is area f(x)=-x^2+3,g(x)=2x+3 ?

The answer to area f(x)=-x^2+3,g(x)=2x+3 is 4/3

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area f(x)=-x^2+3,g(x)=2x+3

area

f (x) = - x^{2} + 3, g (x) = 2 x + 3

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{0} - x^{2} + 3 - (2 x + 3) d x

Solve

\int_{- 2}^{0} - x^{2} + 3 - (2 x + 3) d x : \frac{4}{3}

The area is:

= \frac{4}{3}

x \to - 7 lim (x)

\frac{d}{d x} (5 x - tan (5 x))

y^{^{'}} + y = 5 sin (2 t)

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{3}})

\int \frac{8}{x} d x

What is area f(x)=-x^2+3,g(x)=2x+3 ?
The answer to area f(x)=-x^2+3,g(x)=2x+3 is 4/3