What is the integral of-0.01(1024pi)^2cos(1024pi)x ?

The integral of-0.01(1024pi)^2cos(1024pi)x is -51745.15152…x^2+C

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integral of-0.01(1024pi)^2cos(1024pi)x

\int - 0.01 (1024 π)^{2} cos (1024 π) x d x

- 51745.15152 \dots x^{2} + C

Solution steps

\int - 0.01 (1024 π)^{2} cos (1024 π) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 0.01 (1024 π)^{2} cos (1024 π) \cdot \int x d x

- 0.01 (1024 π)^{2} cos (1024 π) = - 103490.30304 \dots

= - 103490.30304 \dots \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= - 103490.30304 \dots \cdot \frac{x ^{2}}{2}

Simplify

- 103490.30304 \dots \cdot \frac{x ^{2}}{2} : - 51745.15152 \dots x^{2}

= - 51745.15152 \dots x^{2}

Add a constant to the solution

= - 51745.15152 \dots x^{2} + C

\int - cos^{2} (x) d x

\int \frac{1 - cos ( x )}{x} d x

\frac{\partial}{\partial x} ((x^{2} - 1) (y + 2))

\int x - \frac{e ^{x}}{y ^{2}} - 2 y d y

x^{\frac{11}{2}}, 1.2

What is the integral of-0.01(1024pi)^2cos(1024pi)x ?
The integral of-0.01(1024pi)^2cos(1024pi)x is -51745.15152…x^2+C