What is (\partial)/(\partial x)((x^2-1)(y+2)) ?

The answer to (\partial)/(\partial x)((x^2-1)(y+2)) is 2x(y+2)

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(\partial)/(\partial x)((x^2-1)(y+2))

\frac{\partial}{\partial x} ((x^{2} - 1) (y + 2))

2 x (y + 2)

Solution steps

\frac{\partial}{\partial x} ((x^{2} - 1) (y + 2))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y + 2) \frac{\partial}{\partial x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (y + 2) (\frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (1))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (1) = 0

= (y + 2) (2 x - 0)

Simplify

= 2 x (y + 2)

\int x - \frac{e ^{x}}{y ^{2}} - 2 y d y

x^{\frac{11}{2}}, 1.2

\int \frac{1}{1 - 8 x} d x

f (x) = \frac{9 x}{( x + 1 ) ^{2}}, (0, 0)

\frac{1}{s ( s ^{2} + 4 )}

What is (\partial)/(\partial x)((x^2-1)(y+2)) ?
The answer to (\partial)/(\partial x)((x^2-1)(y+2)) is 2x(y+2)