What is the integral of 1/(5x+7) ?

The integral of 1/(5x+7) is 1/5 ln|5x+7|+C

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integral of 1/(5x+7)

\int \frac{1}{5 x + 7} d x

\frac{1}{5} ln ∣ 5 x + 7 ∣ + C

Solution steps

\int \frac{1}{5 x + 7} d x

Apply u-substitution

: \int \frac{1}{5 u} d u

= \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{5} ln ∣ u ∣

Substitute back

u = 5 x + 7

= \frac{1}{5} ln ∣ 5 x + 7 ∣

Add a constant to the solution

= \frac{1}{5} ln ∣ 5 x + 7 ∣ + C

\int_{0}^{1} sin^{2} (2 π x) d x

\frac{d}{d x} (- \frac{1}{( 1 + x ) ^{2}})

\frac{\partial}{\partial x} (2 x y)

f (x) = (9 - 6 x^{2})^{2}

(2 x + y + 1) y^{^{'}} = 1