What is (\partial)/(\partial x)(1/4 x^2*y) ?

The answer to (\partial)/(\partial x)(1/4 x^2*y) is (xy)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(1/4 x^2*y)

\frac{\partial}{\partial x} (\frac{1}{4} x^{2} \cdot y)

\frac{x y}{2}

Solution steps

\frac{\partial}{\partial x} (\frac{1}{4} x^{2} y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} y \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} y \cdot 2 x^{2 - 1}

Simplify

\frac{1}{4} y \cdot 2 x^{2 - 1} : \frac{x y}{2}

= \frac{x y}{2}

\frac{d y}{d x} - \frac{4 y}{x} = \frac{y ^{4}}{x ^{2}}

\frac{\partial}{\partial x} (x e^{(\frac{x}{y})})

f (x) = (\frac{x}{2})^{4}

f (x) = (x - 1)^{\frac{2}{3}}

n = 0 \sum \infty x^{4 n}

What is (\partial)/(\partial x)(1/4 x^2*y) ?
The answer to (\partial)/(\partial x)(1/4 x^2*y) is (xy)/2