What is the solution for (dy)/(dx)=(sin^2(2x))(cos^2(y)) ?

The solution for (dy)/(dx)=(sin^2(2x))(cos^2(y)) is y=arctan(1/2 (x-1/4 sin(4x))+c_{1})+pin

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(dy)/(dx)=(sin^2(2x))(cos^2(y))

\frac{d y}{d x} = (sin^{2} (2 x)) (cos^{2} (y))

y = arctan (\frac{1}{2} (x - \frac{1}{4} sin (4 x)) + c_{1}) + πn

Solution steps

\frac{d y}{d x} = (sin^{2} (2 x)) (cos^{2} (y))

Solve separable ODE:

y = arctan (\frac{1}{2} (x - \frac{1}{4} sin (4 x)) + c_{1}) + πn

y = arctan (\frac{1}{2} (x - \frac{1}{4} sin (4 x)) + c_{1}) + πn

t \frac{d y}{d t} = t^{3} + 20 t^{3} y

\int 1.5 sin (- x + 2) d x

y = cos (x) - x sin (x)

f (x) = x^{\frac{1}{6}}

\frac{d}{d x} (sin^{8} (5 x^{2} + 8))

What is the solution for (dy)/(dx)=(sin^2(2x))(cos^2(y)) ?
The solution for (dy)/(dx)=(sin^2(2x))(cos^2(y)) is y=arctan(1/2 (x-1/4 sin(4x))+c_{1})+pin