What is the sum from k=1 to infinity of k/(2^k) ?

The sum from k=1 to infinity of k/(2^k) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from k=1 to infinity of k/(2^k)

k = 1 \sum \infty \frac{k}{2 ^{k}}

converges

Solution steps

k = 1 \sum \infty \frac{k}{2 ^{k}}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (cosh (x^{2}))

\frac{\partial}{\partial p} (p^{3} q^{2} + 2 pq + \frac{p}{q})

\int \frac{3 x ^{2}}{x ^{3} - 1} d x

f (x) = (ln (x^{5}))^{2}

What is the sum from k=1 to infinity of k/(2^k) ?
The sum from k=1 to infinity of k/(2^k) is converges