What is the solution for y(x+y+1)dx+2xydy=0 ?

The solution for y(x+y+1)dx+2xydy=0 is y=-x/3-1+(c_{1})/(sqrt(x))

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y(x+y+1)dx+2xydy=0

y (x + y + 1) d x + 2 x y d y = 0

y = - \frac{x}{3} - 1 + \frac{c _{1}}{x}

Solution steps

y (x + y + 1) d x + 2 x y d y = 0

Solve linear ODE:

y = - \frac{x}{3} - 1 + \frac{c _{1}}{x}

y = - \frac{x}{3} - 1 + \frac{c _{1}}{x}

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\frac{d}{d x} (x^{\frac{4}{5}} - x^{\frac{2}{3}})

\int \frac{2 x}{x + 3} d x

\frac{d}{d x} (ln (\frac{5 x ^{3} sin ( - 5 x )}{3 - x}))

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What is the solution for y(x+y+1)dx+2xydy=0 ?
The solution for y(x+y+1)dx+2xydy=0 is y=-x/3-1+(c_{1})/(sqrt(x))