What is the integral from 2 to infinity of e^{-3x} ?

The integral from 2 to infinity of e^{-3x} is 1/(3e^6)

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integral from 2 to infinity of e^{-3x}

\int_{2}^{\infty} e^{- 3 x} d x

\frac{1}{3 e ^{6}}

Decimal Notation

0.00082 \dots

Solution steps

\int_{2}^{\infty} e^{- 3 x} d x

Compute the indefinite integral:

\int e^{- 3 x} d x = - \frac{1}{3} e^{- 3 x} + C

Compute the boundaries:

\int_{2}^{\infty} e^{- 3 x} d x = 0 - (- \frac{1}{3 e ^{6}})

= 0 - (- \frac{1}{3 e ^{6}})

Simplify

= \frac{1}{3 e ^{6}}

(2, 5), (8, - 4)

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What is the integral from 2 to infinity of e^{-3x} ?
The integral from 2 to infinity of e^{-3x} is 1/(3e^6)