What is the d/(dt)(7/(sqrt(t))) ?

The d/(dt)(7/(sqrt(t))) is -7/(2t^{3/2)}

What is the first d/(dt)(7/(sqrt(t))) ?

The first d/(dt)(7/(sqrt(t))) is -7/(2t^{3/2)}

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\frac{d}{d t} (\frac{7}{t})

- \frac{7}{2 t ^{\frac{3}{2}}}

Solution steps

\frac{d}{d t} (\frac{7}{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d t} (t^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- \frac{1}{2} t^{- \frac{1}{2} - 1})

Simplify

7 (- \frac{1}{2} t^{- \frac{1}{2} - 1}) : - \frac{7}{2 t ^{\frac{3}{2}}}

= - \frac{7}{2 t ^{\frac{3}{2}}}

\frac{sin ( ln ( 4 ) x ^{2} )}{x}

f (x) = x - 2

\frac{d}{d x} (2 x + 2 y \frac{d y}{d x})

y = 2 x, y = \frac{( x ^{2} )}{4}

\int 5 x^{4} e^{4 x^{5}} d x

What is the d/(dt)(7/(sqrt(t))) ?
The d/(dt)(7/(sqrt(t))) is -7/(2t^{3/2)}
What is the first d/(dt)(7/(sqrt(t))) ?
The first d/(dt)(7/(sqrt(t))) is -7/(2t^{3/2)}