What is the integral of (4x+7)/(x^2+1) ?

The integral of (4x+7)/(x^2+1) is 2ln|x^2+1|+7arctan(x)+C

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integral of (4x+7)/(x^2+1)

\int \frac{4 x + 7}{x ^{2} + 1} d x

2 ln x^{2} + 1 + 7 arctan (x) + C

Solution steps

\int \frac{4 x + 7}{x ^{2} + 1} d x

Expand

\frac{4 x + 7}{x ^{2} + 1} : \frac{4 x}{x ^{2} + 1} + \frac{7}{x ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4 x}{x ^{2} + 1} d x + \int \frac{7}{x ^{2} + 1} d x

\int \frac{4 x}{x ^{2} + 1} d x = 2 ln x^{2} + 1

\int \frac{7}{x ^{2} + 1} d x = 7 arctan (x)

= 2 ln x^{2} + 1 + 7 arctan (x)

Add a constant to the solution

= 2 ln x^{2} + 1 + 7 arctan (x) + C

\int e^{- 2 x} sin (3 x) d x

f (x) = x^{2} sin (2 x)

\int \frac{1}{- 2 x ^{2} - x + 1} d x

y^{^{''}} - y^{^{'}} = 1

\int \frac{4 ^{x} + 1 0 ^{x}}{2 ^{x}} d x

What is the integral of (4x+7)/(x^2+1) ?
The integral of (4x+7)/(x^2+1) is 2ln|x^2+1|+7arctan(x)+C