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Popular >

y^'=(y-x)/x

Solution

y^{^{'}} = \frac{y - x}{x}

Solution

y = - ln (x) x + c_{1} x

Solution steps

y^{'} (x) = \frac{y - x}{x}

Solve linear ODE:

y = - ln (x) x + c_{1} x

y = - ln (x) x + c_{1} x

Popular Examples

(\partial)/(\partial x)(4x^5y)

\frac{\partial}{\partial x} (4 x^{5} y)

(\partial)/(\partial x)((x^2-1)/(x^2+x+1))

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x ^{2} + x + 1})

integral of 2^r

\int 2^{r} d r

derivative of f(x)=sqrt(3+x)derivative of

f (x) = 3 + x

derivative of x^2*sec(1/x)derivative of

x^{2} \cdot sec (\frac{1}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y-x)/x ?
The solution for y^'=(y-x)/x is y=-ln(x)x+c_{1}x