What is the derivative of f(x)=sqrt(3+x) ?

The derivative of f(x)=sqrt(3+x) is 1/(2sqrt(3+x))

What is the first derivative of f(x)=sqrt(3+x) ?

The first derivative of f(x)=sqrt(3+x) is 1/(2sqrt(3+x))

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derivative of

f (x) = 3 + x

\frac{1}{2 3 + x}

Solution steps

\frac{d}{d x} (3 + x)

Apply the chain rule:

\frac{1}{2 3 + x} \frac{d}{d x} (3 + x)

= \frac{1}{2 3 + x} \frac{d}{d x} (3 + x)

\frac{d}{d x} (3 + x) = 1

= \frac{1}{2 3 + x} \cdot 1

Simplify

= \frac{1}{2 3 + x}

x^{2} \cdot sec (\frac{1}{x})

\int_{1}^{3} (4 x^{3} + 2) d x

\int \frac{1}{( 2 - 5 x ) ^{2}} d x

\frac{s + 2}{s ^{2} + 4}

f (x) = \frac{3 x}{x - 2}, (4, 6)

What is the derivative of f(x)=sqrt(3+x) ?
The derivative of f(x)=sqrt(3+x) is 1/(2sqrt(3+x))
What is the first derivative of f(x)=sqrt(3+x) ?
The first derivative of f(x)=sqrt(3+x) is 1/(2sqrt(3+x))