What is the tangent of f(x)=(3x)/(x-2),(4,6) ?

The tangent of f(x)=(3x)/(x-2),(4,6) is y=-3/2 x+12

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tangent of f(x)=(3x)/(x-2),(4,6)

tangent of

f (x) = \frac{3 x}{x - 2}, (4, 6)

y = - \frac{3}{2} x + 12

Solution steps

Find the slope of

f (x) = \frac{3 x}{x - 2} : \frac{df ( x )}{d x} = - \frac{6}{( x - 2 ) ^{2}}

Compute the slope of

f (x) = \frac{3 x}{x - 2}

(4, 6) : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(4, 6) : y = - \frac{3}{2} x + 12

y = - \frac{3}{2} x + 12

\frac{4}{r ^{3}}

\int \frac{2 x + 3}{x ^{2} - 5 x + 4} d x

\int \frac{1}{6} x d x

\frac{x}{3}

\int - 2 y^{2} + 4 x - 5 d x

What is the tangent of f(x)=(3x)/(x-2),(4,6) ?
The tangent of f(x)=(3x)/(x-2),(4,6) is y=-3/2 x+12