What is the integral of-2y^2+4x-5 ?

The integral of-2y^2+4x-5 is -5x-2y^2x+2x^2+C

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integral of-2y^2+4x-5

\int - 2 y^{2} + 4 x - 5 d x

- 5 x - 2 y^{2} x + 2 x^{2} + C

Solution steps

\int - 2 y^{2} + 4 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 5 d x - \int 2 y^{2} d x + \int 4 x d x

\int 5 d x = 5 x

\int 2 y^{2} d x = 2 y^{2} x

\int 4 x d x = 2 x^{2}

= - 5 x - 2 y^{2} x + 2 x^{2}

Add a constant to the solution

= - 5 x - 2 y^{2} x + 2 x^{2} + C

f (x) = x - 4

8 x + \frac{d y}{d x} = 0

t \to 0 lim (\frac{u - ln ( k )}{t})

\int (x^{2} + 2 x + 1)^{20} d x

What is the integral of-2y^2+4x-5 ?
The integral of-2y^2+4x-5 is -5x-2y^2x+2x^2+C