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Popular >

8x+(dy)/(dx)=0

Solution

8 x + \frac{d y}{d x} = 0

Solution

y = - 4 x^{2} + c_{1}

Solution steps

8 x + \frac{d y}{d x} = 0

Substitute

\frac{d y}{d x}

with

y^{'} (x)

8 x + y^{^{'}} (x) = 0

Isolate

y^{'} (x) : y^{'} (x) = - 8 x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 8 x d x

\int - 8 x d x = - 4 x^{2} + c_{1}

y = - 4 x^{2} + c_{1}

Popular Examples

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t \to 0 lim (\frac{u - ln ( k )}{t})

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\int (x^{2} + 2 x + 1)^{20} d x

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\frac{d y}{d t} = \frac{t}{y}

integral of 1/(x+x^{1/3)}

\int \frac{1}{x + x ^{\frac{1}{3}}} d x

Frequently Asked Questions (FAQ)

What is the solution for 8x+(dy)/(dx)=0 ?
The solution for 8x+(dy)/(dx)=0 is y=-4x^2+c_{1}