What is the tangent of 2/x ?

The tangent of 2/x is y=-2/(a_{0)^2}x+4/(a_{0)}

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tangent of 2/x

tangent of

\frac{2}{x}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}})

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

x = a_{0} : m = - \frac{2}{a _{0}^{2}}

Find the line with slope m=

- \frac{2}{a _{0}^{2}}

and passing through

(a_{0}, \frac{2}{a _{0}}) : y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

1 (t - 4)

x \to 0 + lim (sin^{x} (x))

x \to 1 lim (2 x^{2} + x - 1)

\int 3 e^{x} + 7 sec^{2} (x) d x

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{y}})