What is (\partial)/(\partial x)(x^2-2y^2+4) ?

The answer to (\partial)/(\partial x)(x^2-2y^2+4) is 2x

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(\partial)/(\partial x)(x^2-2y^2+4)

\frac{\partial}{\partial x} (x^{2} - 2 y^{2} + 4)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 y^{2} + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 y^{2}) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

\frac{\partial}{\partial x} (4) = 0

= 2 x - 0 + 0

Simplify

= 2 x

\int 4 x^{3} e^{x} d x

\frac{1}{x}, 0, y = 1, y = e

x \to 3 lim (x^{3} + 6 x)

\int \frac{x - 4}{x ^{2} + 5 x + 6} d x

y = (\frac{cos ( x )}{1 - sin ( x )})^{2}

What is (\partial)/(\partial x)(x^2-2y^2+4) ?
The answer to (\partial)/(\partial x)(x^2-2y^2+4) is 2x