What is inverse oflaplace 1/(s-10) ?

The answer to inverse oflaplace 1/(s-10) is e^{10t}

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inverse oflaplace 1/(s-10)

inverse laplace

\frac{1}{s - 10}

e^{10 t}

Solution steps

L^{- 1} {\frac{1}{s - 10}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 10}} = e^{10 t}

= e^{10 t}

\frac{\partial}{\partial x} (cos (y) sin (x))

\frac{d}{d x} (\frac{x + 1}{x + 2})

\int \frac{1}{( 2 x + 5 )} d x

\frac{d}{d x} (\frac{1}{x ^{2}})

\int \frac{2}{1 + x ^{4}} d x

What is inverse oflaplace 1/(s-10) ?
The answer to inverse oflaplace 1/(s-10) is e^{10t}