What is the derivative of 8x(x^2+3^3) ?

The derivative of 8x(x^2+3^3) is 8((x^2+3)^3+6x^2(x^2+3)^2)

What is the first derivative of 8x(x^2+3^3) ?

The first derivative of 8x(x^2+3^3) is 8((x^2+3)^3+6x^2(x^2+3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (8 x (x^{2} + 3)^{3})

8 ((x^{2} + 3)^{3} + 6 x^{2} (x^{2} + 3)^{2})

Solution steps

\frac{d}{d x} (8 x (x^{2} + 3)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x (x^{2} + 3)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (x^{2} + 3)^{3}

= 8 (\frac{d x}{d x} (x^{2} + 3)^{3} + \frac{d}{d x} ((x^{2} + 3)^{3}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 3)^{3}) = 6 x (x^{2} + 3)^{2}

= 8 (1 \cdot (x^{2} + 3)^{3} + 6 x (x^{2} + 3)^{2} x)

Simplify

8 (1 \cdot (x^{2} + 3)^{3} + 6 x (x^{2} + 3)^{2} x) : 8 ((x^{2} + 3)^{3} + 6 x^{2} (x^{2} + 3)^{2})

= 8 ((x^{2} + 3)^{3} + 6 x^{2} (x^{2} + 3)^{2})

f (x) = 16 - x^{2}

(4 x)^{^{'}}

\int (5 x^{2} + 5 x + 3)^{4} (2 x + 1) d x

\int \frac{- x}{( x ^{2} + 1 )} d x

\frac{d}{d x} (x^{6} (x - 1)^{5})

What is the derivative of 8x(x^2+3^3) ?
The derivative of 8x(x^2+3^3) is 8((x^2+3)^3+6x^2(x^2+3)^2)
What is the first derivative of 8x(x^2+3^3) ?
The first derivative of 8x(x^2+3^3) is 8((x^2+3)^3+6x^2(x^2+3)^2)