What is the limit as x approaches 0 of (3x)/(2x^2+x) ?

The limit as x approaches 0 of (3x)/(2x^2+x) is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (3x)/(2x^2+x)

x \to 0 lim (\frac{3 x}{2 x ^{2} + x})

3

Solution steps

x \to 0 lim (\frac{3 x}{2 x ^{2} + x})

Simplify

\frac{3 x}{2 x ^{2} + x} : \frac{3}{2 x + 1}

= x \to 0 lim (\frac{3}{2 x + 1})

Plug in the value

x = 0

= \frac{3}{2 \cdot 0 + 1}

Simplify

= 3

\int (e^{4 x} - 4)^{\frac{1}{5}} \cdot 8 e^{4 x} d x

\frac{2 x}{1 - cot ( x )}

x \to 0 lim (\frac{1}{x + \frac{1}{x}})

\frac{8 s}{3 ( s ^{2} - 16 ) ^{2}}

3 y + x^{4} y^{^{'}} = 2 x y

What is the limit as x approaches 0 of (3x)/(2x^2+x) ?
The limit as x approaches 0 of (3x)/(2x^2+x) is 3