What is the solution for (dv)/(dt)=-ktv^2,v(0)=50 ?

The solution for (dv)/(dt)=-ktv^2,v(0)=50 is v=(50)/(25kt^2+1)

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(dv)/(dt)=-ktv^2,v(0)=50

\frac{d v}{d t} = - k t v^{2}, v (0) = 50

v = \frac{50}{25 k t ^{2} + 1}

Solution steps

\frac{d v}{d t} = - k t v^{2}

Solve separable ODE:

v = \frac{50}{25 k t ^{2} + 1}

v = \frac{50}{25 k t ^{2} + 1}

sin (3 x)

h (θ) = θ cos (θ)

\int \frac{x y ^{2}}{x ^{2} + 1} d y

x \to - \infty lim (tanh (x))

\int sec (t) tan (t) d t

What is the solution for (dv)/(dt)=-ktv^2,v(0)=50 ?
The solution for (dv)/(dt)=-ktv^2,v(0)=50 is v=(50)/(25kt^2+1)