What is the derivative of (x^3)/7 ?

The derivative of (x^3)/7 is (3x^2)/7

What is the first derivative of (x^3)/7 ?

The first derivative of (x^3)/7 is (3x^2)/7

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derivative of

\frac{x ^{3}}{7}

\frac{3 x ^{2}}{7}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{7} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{7} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{7} \cdot 3 x^{3 - 1} : \frac{3 x ^{2}}{7}

= \frac{3 x ^{2}}{7}

\int 3 x x + 2 d x

\frac{\partial}{\partial y} (x^{4} y^{3} + 8 x^{2} y)

f^{^{'''}} + f^{^{''}} + 3 f^{^{'}} - 5 f = 0

s - 1

\int \frac{3 x}{( x ^{2} + 3 ) ^{\frac{1}{3}}} d x

What is the derivative of (x^3)/7 ?
The derivative of (x^3)/7 is (3x^2)/7
What is the first derivative of (x^3)/7 ?
The first derivative of (x^3)/7 is (3x^2)/7