What is laplacetransform s-1 ?

The answer to laplacetransform s-1 is 1/(s^2)-1/s

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laplacetransform s-1

laplace transform

s - 1

\frac{1}{s ^{2}} - \frac{1}{s}

Solution steps

L {s - 1}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {s} - L {1}

L {s} : \frac{1}{s ^{2}}

L {1} : \frac{1}{s}

= \frac{1}{s ^{2}} - \frac{1}{s}

\int \frac{3 x}{( x ^{2} + 3 ) ^{\frac{1}{3}}} d x

\frac{d}{d x} (\frac{( 1 - x ^{2} )}{2 - x})

x \to 3 - lim (\frac{1}{∣ x - 3 ∣})

\int_{0}^{9} x d x

\frac{d}{d x} f (x) = (4 x^{(4)} + 6)^{(3)}

What is laplacetransform s-1 ?
The answer to laplacetransform s-1 is 1/(s^2)-1/s