What is the derivative of ((1-x^2)/(2-x)) ?

The derivative of ((1-x^2)/(2-x)) is (x^2-4x+1)/((2-x)^2)

What is the first derivative of ((1-x^2)/(2-x)) ?

The first derivative of ((1-x^2)/(2-x)) is (x^2-4x+1)/((2-x)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{( 1 - x ^{2} )}{2 - x})

\frac{x ^{2} - 4 x + 1}{( 2 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( 1 - x ^{2} )}{2 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 - x ^{2} ) ( 2 - x ) - \frac{d}{d x} ( 2 - x ) ( 1 - x ^{2} )}{( 2 - x ) ^{2}}

\frac{d}{d x} (1 - x^{2}) = - 2 x

\frac{d}{d x} (2 - x) = - 1

= \frac{( - 2 x ) ( 2 - x ) - ( - 1 ) ( 1 - x ^{2} )}{( 2 - x ) ^{2}}

Simplify

\frac{( - 2 x ) ( 2 - x ) - ( - 1 ) ( 1 - x ^{2} )}{( 2 - x ) ^{2}} : \frac{x ^{2} - 4 x + 1}{( 2 - x ) ^{2}}

= \frac{x ^{2} - 4 x + 1}{( 2 - x ) ^{2}}

x \to 3 - lim (\frac{1}{∣ x - 3 ∣})

\int_{0}^{9} x d x

\frac{d}{d x} f (x) = (4 x^{(4)} + 6)^{(3)}

g (x) = 5 x^{2} - x + 7

\frac{d}{d x} ((8 + 7 x)^{4})

What is the derivative of ((1-x^2)/(2-x)) ?
The derivative of ((1-x^2)/(2-x)) is (x^2-4x+1)/((2-x)^2)
What is the first derivative of ((1-x^2)/(2-x)) ?
The first derivative of ((1-x^2)/(2-x)) is (x^2-4x+1)/((2-x)^2)