en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 1/x , 1/(x^2),2

Solution

area

\frac{1}{x}, \frac{1}{x ^{2}}, 2

Solution

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{1}{x} = \frac{1}{x ^{2}} : x = 1

\frac{1}{x} = 2 : x = \frac{1}{2}

\frac{1}{x ^{2}} = 2 : x = \frac{1}{2}, x = - \frac{1}{2}

Curves not bounded

= No Solution

Popular Examples

integral of (sin(t))/(t^2)

\int \frac{sin ( t )}{t ^{2}} d t

y^{''}+6y^'+9y=(-16e^{-3t})/(t^2+1)

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{- 16 e ^{- 3 t}}{t ^{2} + 1}

inverse oflaplace (s+5)/(s^2+5s+6)inverse laplace

\frac{s + 5}{s ^{2} + 5 s + 6}

derivative of (x-1/(x^2+2x+1))

\frac{d}{d x} (\frac{x - 1}{x ^{2} + 2 x + 1})

integral of (2x)/((x^2+1))

\int \frac{2 x}{( x ^{2} + 1 )} d x

Frequently Asked Questions (FAQ)

What is area 1/x , 1/(x^2),2 ?
The answer to area 1/x , 1/(x^2),2 is No Solution