What is the tangent of f(x)=-3cos(x),\at x=-pi/3 ?

The tangent of f(x)=-3cos(x),\at x=-pi/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2

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tangent of f(x)=-3cos(x),\at x=-pi/3

tangent of

f (x) = - 3 cos (x), at x = - \frac{π}{3}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

Solution steps

Find the tangent point:

(- \frac{π}{3}, - \frac{3}{2})

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

Compute the slope of

f (x) = - 3 cos (x)

x = - \frac{π}{3} : m = - \frac{3 3}{2}

Find the line with slope m=

- \frac{3 3}{2}

and passing through

(- \frac{π}{3}, - \frac{3}{2}) : y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

\int (1 - \frac{1}{x ^{2}}) x x d x

\frac{d}{d x} (3 x^{2} - y^{2})

\int sec (t) sec (t) + tan (t) d t

\int_{0}^{\infty} e^{- ∣ x ∣} d x

\frac{d}{d x} ((3 x^{2} - 9)^{- 12})

What is the tangent of f(x)=-3cos(x),\at x=-pi/3 ?
The tangent of f(x)=-3cos(x),\at x=-pi/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2